(5/4)x^2-3x+(1/5)=0

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Solution for (5/4)x^2-3x+(1/5)=0 equation: 


x in (-oo:+oo)

(5/4)*x^2-(3*x)+1/5 = 0

(5/4)*x^2-3*x+1/5 = 0

5/4*x^2-3*x+1/5 = 0

DELTA = (-3)^2-(1/5*5/4*4)

DELTA = 8

DELTA > 0

x = (8^(1/2)+3)/(5/4*2) or x = (3-8^(1/2))/(5/4*2)

x = 2/5*(2*2^(1/2)+3) or x = 2/5*(3-2*2^(1/2))

x in { 2/5*(3-2*2^(1/2)), 2/5*(2*2^(1/2)+3) }

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